Ideal Gas Law
Chemistry, Physics
Intro: Use a consistent gas constant, e.g., $R = 0.082057\;\mathrm{L\,atm\,mol^{-1}\,K^{-1}}$.
Worked example
- $V=10 L, n=0.5 mol, T=350 K, R=0.082057$
- Use $PV=nRT\Rightarrow P=\dfrac{nRT}{V}$.
- Compute numerator: $nRT=0.5\cdot0.082057\cdot350=14.360$.
- Divide by $V=10$: $P=14.360/10=1.436\,\mathrm{atm}$.
- Round if needed: $P\approx1.44\,\mathrm{atm}$.
- Answer: $\boxed{P\approx1.44\,\text{atm}}$.
FAQs
Temperature units?
Use Kelvin for T when applying $PV=nRT$.
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How this calculator works
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\sin,\lnworks too). - Press Generate a practice question button to generate the derivative and the full reasoning.
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