Projectile Motion
Physics, Mechanics
Intro: Horizontal range (flat ground): $R=\tfrac{v_0^2\sin2\theta}{g}$.
Worked example
- $v0=20 m/s, θ=30°, g=9.8 m/s^2$
- Inputs: $v_0=20$, $\theta=30^\circ\Rightarrow 2\theta=60^\circ$, $g=9.8$.
- Trig: $\sin60^\circ=\tfrac{\sqrt{3}}{2}\approx0.8660$.
- Compute numerator: $v_0^2\sin(2\theta)=400\cdot0.8660=346.40$.
- Divide by $g$: $R=346.40/9.8\approx35.35\,\mathrm{m}$.
- Answer: $\boxed{R\approx35.4\,\text{m}}$.
FAQs
Air resistance?
Ignored in these ideal equations.
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