Question: User: $\lvert x+10 \rvert > 5$
1. **State the problem:** Solve the inequality $$\lvert x+10 \rvert > 5$$.
2. **Recall the definition of absolute value inequality:** For $$\lvert A \rvert > B$$ where $$B > 0$$, the solution is $$A < -B$$ or $$A > B$$.
3. **Apply the rule:** Here, $$A = x+10$$ and $$B = 5$$, so
$$x+10 < -5 \quad \text{or} \quad x+10 > 5$$
4. **Solve each inequality separately:**
- For $$x+10 < -5$$:
$$x < -5 - 10$$
$$x < -15$$
- For $$x+10 > 5$$:
$$x > 5 - 10$$
$$x > -5$$
5. **Combine the solution:**
$$x < -15 \quad \text{or} \quad x > -5$$
6. **Interpretation:** The values of $$x$$ are all numbers less than $$-15$$ or greater than $$-5$$.
**Final answer:** $$x < -15 \quad \text{or} \quad x > -5$$