Question: Find the average rate of change for the given function.
f(x) = \sqrt{4x + 1}; between x = 0 and x = 2
The average rate of change of f(x) between x = 0 and x = 2 is \boxed{\text{?}}.
(Simplify your answer.)
1. **State the problem:** We need to find the average rate of change of the function $$f(x) = \sqrt{4x + 1}$$ between $$x = 0$$ and $$x = 2$$.
2. **Recall the formula:** The average rate of change of a function $$f$$ between $$x = a$$ and $$x = b$$ is given by:
$$\text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a}$$
3. **Evaluate the function at the given points:**
$$f(0) = \sqrt{4(0) + 1} = \sqrt{1} = 1$$
$$f(2) = \sqrt{4(2) + 1} = \sqrt{8 + 1} = \sqrt{9} = 3$$
4. **Apply the formula:**
$$\frac{f(2) - f(0)}{2 - 0} = \frac{3 - 1}{2} = \frac{2}{2}$$
5. **Simplify the fraction:**
$$\frac{\cancel{2}}{\cancel{2}} = 1$$
6. **Conclusion:** The average rate of change of $$f(x)$$ between $$x = 0$$ and $$x = 2$$ is $$1$$.