Subjects algebra

Beanbag Score Bdc5Aa

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Question: In a beanbag toss, players earn $2$ points for each beanbag that lands on the game board and $5$ points for each beanbag that lands in the hole. Let $b$ equal the bags that land on the board. Let $h$ equal the bags that land in the hole. Write an expression to represent a player's total score.
1. **State the problem:** We need to find an expression for the total score based on the number of beanbags landing on the board and in the hole. 2. **Identify variables and points:** - Each beanbag on the board earns $2$ points. - Each beanbag in the hole earns $5$ points. - Let $b$ be the number of beanbags on the board. - Let $h$ be the number of beanbags in the hole. 3. **Write the expression:** The total score $S$ is the sum of points from beanbags on the board and in the hole: $$S = 2b + 5h$$ 4. **Explanation:** - Multiply the number of beanbags on the board $b$ by $2$ points each. - Multiply the number of beanbags in the hole $h$ by $5$ points each. - Add these two amounts to get the total score. **Final answer:** $$\boxed{S = 2b + 5h}$$
5 points2 points