Bus Speed 9B4C06

1. **State the problem:** We need to find the speeds of bus A and bus B given that bus A is 14 mph slower than bus B and both travel different distances in the same time. 2. **Define variables:** Let the speed of bus B be $x$ mph. Then the speed of bus A is $x - 14$ mph. 3. **Use the formula for time:** Time = Distance / Speed. Since both buses travel for the same time, $$\frac{220}{x - 14} = \frac{290}{x}$$ 4. **Solve the equation:** Cross-multiply: $$220 \times x = 290 \times (x - 14)$$ $$220x = 290x - 290 \times 14$$ $$220x = 290x - 4060$$ 5. **Isolate $x$:** $$220x - 290x = -4060$$ $$-70x = -4060$$ 6. **Divide both sides by -70:** $$\cancel{-70}x = \frac{-4060}{\cancel{-70}}$$ $$x = 58$$ 7. **Find speed of bus A:** $$x - 14 = 58 - 14 = 44$$ **Final answer:** - Speed of bus B is $58$ mph. - Speed of bus A is $44$ mph.