Subjects algebra

Chips Price Fa4923

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Question: Raymond and Faris share the price of a bag of chips. Raymond pays 485 cents and Faris pays $1.20 less than Raymond. How much is the bag of chips?
1. **State the problem:** We need to find the total price of the bag of chips shared by Raymond and Faris. 2. **Define variables:** Let the price Raymond pays be $R = 485$ cents. Faris pays $1.20$ less than Raymond, so Faris pays $F = R - 120$ cents (since $1.20 = 120$ cents). 3. **Write the total price formula:** Total price $T = R + F$ 4. **Substitute Faris's payment:** $$T = R + (R - 120)$$ 5. **Simplify:** $$T = 485 + (485 - 120)$$ $$T = 485 + 485 - 120$$ $$T = 970 - 120$$ $$T = 850$$ 6. **Interpret the result:** The total price of the bag of chips is $850$ cents. 7. **Convert to dollars:** $$850 \text{ cents} = \frac{850}{100} = 8.50$$ dollars. **Final answer:** The bag of chips costs $8.50$.