Subjects algebra

Coffee Temperature 253F2E

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Question: The temperature of a cup of coffee can be modeled using the equation $T = -5t + 200$, where $T$ represents the temperature of the coffee in degrees Fahrenheit, and $t$ is the time in minutes since the coffee was poured. • The ____ intercept would be the initial temperature of the coffee. • The ____ intercept represents the number of minutes until the coffee cools to room temperature. • The slope indicates that the coffee's temperature is ____ at 5°F/min.
1. **State the problem:** We have the temperature model $$T = -5t + 200$$ where $T$ is temperature in °F and $t$ is time in minutes. 2. **Identify intercepts:** - The $t$-intercept is where $T=0$. - The $T$-intercept is where $t=0$. 3. **Find the $T$-intercept (initial temperature):** Substitute $t=0$: $$T = -5(0) + 200 = 200$$ So, the $T$-intercept is $200$°F, which is the initial temperature of the coffee. 4. **Find the $t$-intercept (time when coffee cools to room temperature):** Set $T=0$ and solve for $t$: $$0 = -5t + 200$$ $$5t = 200$$ $$t = \frac{200}{5}$$ $$t = 40$$ So, the coffee cools to room temperature after $40$ minutes. 5. **Interpret the slope:** The slope is $-5$, meaning the temperature decreases by $5$°F every minute. **Final answers:** - The $T$-intercept is the initial temperature of the coffee: $200$°F. - The $t$-intercept represents the number of minutes until the coffee cools to room temperature: $40$ minutes. - The slope indicates the coffee's temperature decreases at $5$°F per minute.