Question: Subtract.
$(9 + 4i) - (2 + 2i) = \square + \square i$
(Type integers.)
1. The problem is to subtract the complex numbers $(9 + 4i)$ and $(2 + 2i)$.
2. The formula for subtracting complex numbers is:
$$ (a + bi) - (c + di) = (a - c) + (b - d)i $$
where $a$, $b$, $c$, and $d$ are integers.
3. Applying the formula:
$$ (9 + 4i) - (2 + 2i) = (9 - 2) + (4 - 2)i $$
4. Simplify the subtraction:
$$ 7 + 2i $$
5. Therefore, the result is $7 + 2i$.
This means the real part is $7$ and the imaginary part is $2$.