1. The problem asks to determine the constant of proportionality $k$ for the first table and fill in the missing values. 2. Recall that in a proportional relationship, $y = kx$, where $k$ is the constant of proportionality. 3. From the first table, use the known pairs to find $k$. For example, when $x=13$, $y=78$, so: $$k = \frac{y}{x} = \frac{78}{13} = 6$$ 4. Now use $k=6$ to find the missing values: - When $x=1$, $y = 6 \times 1 = 6$ - When $y=24$, $x = \frac{24}{6} = 4$ - When $y=42$, $x = \frac{42}{6} = 7$ - When $x=10$, $y = 6 \times 10 = 60$ 5. The completed first table is: | x | y | |---|---| | 1 | 6 | | 4 | 24| | 7 | 42| |10 | 60| |13 | 78| Final answer: $k=6$ for the first table.