1. **State the problem:** We are given a table showing the distance an object travels over time and asked to find the distance traveled in 5 seconds assuming a constant rate of change. 2. **Identify the formula:** Since the object travels at a constant rate, the relationship between distance ($d$) and time ($t$) is linear and can be expressed as: $$d = rt$$ where $r$ is the rate of change (speed). 3. **Find the rate of change:** From the table: - At $t=1$ second, $d=1.5$ meters - At $t=2$ seconds, $d=3.0$ meters Calculate the rate $r$: $$r = \frac{\text{change in distance}}{\text{change in time}} = \frac{3.0 - 1.5}{2 - 1} = \frac{1.5}{1} = 1.5 \text{ m/s}$$ 4. **Calculate distance at 5 seconds:** Using $d = rt$: $$d = 1.5 \times 5 = 7.5 \text{ meters}$$ 5. **Answer:** The object travels 7.5 meters in 5 seconds. **Final answer: C 7.5 m**