1. The problem states that an object travels at a constant rate and provides a table of time (s) and distance (m): | Time (s) | Distance (m) | |----------|--------------| | 1 | 1.5 | | 2 | 3.0 | | 3 | 4.5 | We need to find the distance traveled in 5 seconds. 2. Since the object travels at a constant rate, the relationship between distance and time is linear. The formula for distance with constant speed is: $$\text{distance} = \text{rate} \times \text{time}$$ 3. Calculate the rate of change (speed) using the data points. For example, between 1s and 2s: $$\text{rate} = \frac{3.0 - 1.5}{2 - 1} = \frac{1.5}{1} = 1.5 \text{ m/s}$$ 4. Confirm the rate is constant by checking another interval, between 2s and 3s: $$\frac{4.5 - 3.0}{3 - 2} = \frac{1.5}{1} = 1.5 \text{ m/s}$$ The rate is constant at 1.5 m/s. 5. Use the rate to find the distance at 5 seconds: $$\text{distance} = 1.5 \times 5 = 7.5 \text{ m}$$ 6. The correct answer is C: 7.5 m.