1. The problem involves understanding and comparing the two expressions: $$\frac{x^2 - y^2}{2}$$ and $$\frac{x^2 - y^2}{2c}$$ 2. These are fractions where the numerator is the difference of squares $x^2 - y^2$. 3. Recall the difference of squares factorization formula: $$a^2 - b^2 = (a - b)(a + b)$$ Applying this to the numerator: $$x^2 - y^2 = (x - y)(x + y)$$ 4. So the expressions become: $$\frac{(x - y)(x + y)}{2}$$ and $$\frac{(x - y)(x + y)}{2c}$$ 5. The difference between the two expressions is the denominator: the first has $2$, the second has $2c$. 6. This means the second expression is the first expression divided by $c$: $$\frac{x^2 - y^2}{2c} = \frac{1}{c} \times \frac{x^2 - y^2}{2}$$ 7. If $c$ is a constant, the second expression scales the first by $\frac{1}{c}$. Final answer: $$\frac{x^2 - y^2}{2} \quad \text{and} \quad \frac{x^2 - y^2}{2c} = \frac{1}{c} \times \frac{x^2 - y^2}{2}$$