Subjects algebra

Equation Error Correction 5645Da

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Question: Describe and correct any error a student may have made when solving the equation $0.15(y - 0.2) = 2 - 0.5(1 - y)$. $0.15(y - 0.2) = 2 - 0.5(1 - y)$ $0.15y - 0.3 = 2 - 0.5 + 0.5y$ $0.15y - 0.3 = 1.5 + 0.5y$ $100(0.15y - 0.3) = 100(1.5 + 0.5y)$ $15y - 30 = 150 + 50y$ $15y - 30 - 15y - 150 = 150 + 50y - 15y - 150$ $-180 = 35y$ $180 \over 35 = y$ The student first made an error when writing $0.15y - 0.3 = 1.5 + 0.5y$. The expression on the left side of that equation should be $2$. The correct answer is $y = 3$. Simplify your answers.
1. **State the problem:** Solve the equation $$0.15(y - 0.2) = 2 - 0.5(1 - y)$$ and identify any errors in the student's solution. 2. **Distribute terms:** $$0.15(y - 0.2) = 0.15y - 0.15 \times 0.2 = 0.15y - 0.03$$ $$-0.5(1 - y) = -0.5 + 0.5y$$ So the equation becomes: $$0.15y - 0.03 = 2 - 0.5 + 0.5y$$ 3. **Simplify the right side:** $$2 - 0.5 = 1.5$$ So: $$0.15y - 0.03 = 1.5 + 0.5y$$ 4. **Identify the student's error:** The student wrote the left side as $$0.15y - 0.3$$ instead of $$0.15y - 0.03$$. This is a mistake in multiplying $$0.15 \times 0.2$$. 5. **Correct the equation:** $$0.15y - 0.03 = 1.5 + 0.5y$$ 6. **Eliminate decimals by multiplying both sides by 100:** $$100(0.15y - 0.03) = 100(1.5 + 0.5y)$$ $$15y - 3 = 150 + 50y$$ 7. **Bring all terms to one side:** $$15y - 3 - 15y - 150 = 150 + 50y - 15y - 150$$ $$-153 = 35y$$ 8. **Solve for $$y$$:** $$y = \frac{-153}{35} = -\frac{153}{35}$$ 9. **Check the sign and calculation:** Since the right side was $$1.5 + 0.5y$$, subtracting $$0.5y$$ from both sides: $$0.15y - 0.5y = 1.5 + 0.03$$ $$-0.35y = 1.53$$ $$y = \frac{1.53}{-0.35} = -4.3714$$ 10. **Re-examine the original problem:** The student's original error was in the multiplication step. **Correct solution steps:** $$0.15(y - 0.2) = 2 - 0.5(1 - y)$$ $$0.15y - 0.03 = 2 - 0.5 + 0.5y$$ $$0.15y - 0.03 = 1.5 + 0.5y$$ Subtract $$0.5y$$ from both sides: $$0.15y - 0.5y - 0.03 = 1.5$$ $$-0.35y - 0.03 = 1.5$$ Add $$0.03$$ to both sides: $$-0.35y = 1.53$$ Divide both sides by $$-0.35$$: $$y = \frac{1.53}{-0.35} = -4.3714$$ **Final answer:** $$y \approx -4.37$$ **Summary:** The student's error was incorrectly calculating $$0.15 \times 0.2$$ as $$0.3$$ instead of $$0.03$$, which led to an incorrect equation and solution. The correct solution is $$y \approx -4.37$$, not $$3$$.