Question: Select all the pairs of equivalent expressions.
$4^{-3} \cdot 4$ and $16^{-2}$
$4^{-3} \cdot 5^{2}$ and $20^{-1}$
$\frac{3^{5}}{3^{8}}$ and $3^{-3}$
$(5^{2})^{-6}$ and $5^{-4}$
$\left(\frac{3}{4}\right)^{-2}$ and $\left(\frac{4}{3}\right)^{2}$
1. **State the problem:** We need to determine which pairs of expressions are equivalent.
2. **Recall exponent rules:**
- $a^{m} \cdot a^{n} = a^{m+n}$
- $\frac{a^{m}}{a^{n}} = a^{m-n}$
- $(a^{m})^{n} = a^{m \cdot n}$
- $a^{-m} = \frac{1}{a^{m}}$
- $\left(\frac{a}{b}\right)^{-m} = \left(\frac{b}{a}\right)^{m}$
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3. **Check each pair:**
**Pair 1:** $4^{-3} \cdot 4$ and $16^{-2}$
- Simplify $4^{-3} \cdot 4 = 4^{-3} \cdot 4^{1} = 4^{-3+1} = 4^{-2}$
- Simplify $16^{-2} = (4^{2})^{-2} = 4^{2 \cdot (-2)} = 4^{-4}$
- Since $4^{-2} \neq 4^{-4}$, these are **not equivalent**.
**Pair 2:** $4^{-3} \cdot 5^{2}$ and $20^{-1}$
- Simplify $4^{-3} \cdot 5^{2}$ stays as is.
- Simplify $20^{-1} = \frac{1}{20} = \frac{1}{4 \cdot 5}$
- $4^{-3} = \frac{1}{4^{3}} = \frac{1}{64}$ and $5^{2} = 25$, so $4^{-3} \cdot 5^{2} = \frac{25}{64}$
- $20^{-1} = \frac{1}{20} = 0.05$, $\frac{25}{64} \approx 0.390625$
- Not equal, so **not equivalent**.
**Pair 3:** $\frac{3^{5}}{3^{8}}$ and $3^{-3}$
- Simplify $\frac{3^{5}}{3^{8}} = 3^{5-8} = 3^{-3}$
- Both sides equal $3^{-3}$, so **equivalent**.
**Pair 4:** $(5^{2})^{-6}$ and $5^{-4}$
- Simplify $(5^{2})^{-6} = 5^{2 \cdot (-6)} = 5^{-12}$
- Compare with $5^{-4}$
- Since $5^{-12} \neq 5^{-4}$, **not equivalent**.
**Pair 5:** $\left(\frac{3}{4}\right)^{-2}$ and $\left(\frac{4}{3}\right)^{2}$
- Simplify $\left(\frac{3}{4}\right)^{-2} = \left(\frac{4}{3}\right)^{2}$ by the negative exponent rule
- Both sides are equal, so **equivalent**.
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**Final answer:** The equivalent pairs are:
- $\frac{3^{5}}{3^{8}}$ and $3^{-3}$
- $\left(\frac{3}{4}\right)^{-2}$ and $\left(\frac{4}{3}\right)^{2}$