Subjects algebra

Expand Binomials 08C783

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Question: User: $(x+7)(x+2)$ $(x+7)(x-2)$ $(x-7)(x+2)$ The three expressions are shown in the center, with the top one near the upper-center circle, the second one centered below it, and the third one slightly lower in the center. position_hint: center
1. **Problem Statement:** We are given three expressions to expand: $$ (x+7)(x+2), \quad (x+7)(x-2), \quad (x-7)(x+2) $$ 2. **Formula Used:** To expand expressions of the form $(a+b)(c+d)$, use the distributive property (FOIL method): $$ (a+b)(c+d) = ac + ad + bc + bd $$ 3. **Expand each expression:** - For $$ (x+7)(x+2) $$: $$ x \cdot x + x \cdot 2 + 7 \cdot x + 7 \cdot 2 = x^2 + 2x + 7x + 14 $$ Combine like terms: $$ x^2 + (2x + 7x) + 14 = x^2 + 9x + 14 $$ - For $$ (x+7)(x-2) $$: $$ x \cdot x + x \cdot (-2) + 7 \cdot x + 7 \cdot (-2) = x^2 - 2x + 7x - 14 $$ Combine like terms: $$ x^2 + (-2x + 7x) - 14 = x^2 + 5x - 14 $$ - For $$ (x-7)(x+2) $$: $$ x \cdot x + x \cdot 2 + (-7) \cdot x + (-7) \cdot 2 = x^2 + 2x - 7x - 14 $$ Combine like terms: $$ x^2 + (2x - 7x) - 14 = x^2 - 5x - 14 $$ 4. **Final answers:** $$ (x+7)(x+2) = x^2 + 9x + 14 $$ $$ (x+7)(x-2) = x^2 + 5x - 14 $$ $$ (x-7)(x+2) = x^2 - 5x - 14 $$