Question: Math LF7
7d $(x+y)(7x+2y-1)$
$7x^2+2xy+2y^2-x-y$
1. **State the problem:**
We are asked to expand and simplify the expression $(x+y)(7x+2y-1)$ and verify if it equals $7x^2+2xy+2y^2-x-y$.
2. **Recall the distributive property:**
$$(a+b)(c+d+e) = a(c+d+e) + b(c+d+e)$$
3. **Apply the distributive property:**
$$(x+y)(7x+2y-1) = x(7x+2y-1) + y(7x+2y-1)$$
4. **Multiply each term:**
$$x \cdot 7x = 7x^2$$
$$x \cdot 2y = 2xy$$
$$x \cdot (-1) = -x$$
$$y \cdot 7x = 7xy$$
$$y \cdot 2y = 2y^2$$
$$y \cdot (-1) = -y$$
5. **Combine all terms:**
$$7x^2 + 2xy - x + 7xy + 2y^2 - y$$
6. **Combine like terms:**
$$2xy + 7xy = 9xy$$
7. **Final simplified expression:**
$$7x^2 + 9xy + 2y^2 - x - y$$
8. **Compare with given expression:**
Given: $$7x^2 + 2xy + 2y^2 - x - y$$
Our result: $$7x^2 + 9xy + 2y^2 - x - y$$
They are not equal because the coefficient of $xy$ differs ($2xy$ vs $9xy$).
**Answer:** The expanded form of $(x+y)(7x+2y-1)$ is $$7x^2 + 9xy + 2y^2 - x - y$$ which does not equal $$7x^2 + 2xy + 2y^2 - x - y$$.