1. The problem states: If $2^x = 18$, then find the value of $2^{\log 18}$. 2. First, recall the definition of logarithm: $\log a$ means the logarithm base 10 of $a$. 3. The expression $2^{\log 18}$ means 2 raised to the power of $\log 18$. 4. We know from the problem that $2^x = 18$. Taking the logarithm base 10 on both sides gives: $$\log(2^x) = \log 18$$ 5. Using the logarithm power rule: $$x \log 2 = \log 18$$ 6. Solving for $x$: $$x = \frac{\log 18}{\log 2}$$ 7. Now, substitute $x$ back into $2^{\log 18}$: $$2^{\log 18} = 2^{x \log 2}$$ 8. Since $x = \frac{\log 18}{\log 2}$, then: $$2^{\log 18} = 2^{\left(\frac{\log 18}{\log 2}\right) \log 2} = 2^{\log 18}$$ 9. Simplify the exponent: $$\left(\frac{\log 18}{\log 2}\right) \log 2 = \log 18$$ 10. So, $2^{\log 18} = 10^{\log 18} = 18$ because $10^{\log a} = a$. **Final answer:** $$2^{\log 18} = 18$$