Question: Graph the function $f(x) = -6\left(\frac{4}{3}\right)^x$ and answer the following:
• Is the function increasing or decreasing?
• What are the domain and range of $f(x)$?
• What is the y-intercept of the graph of $f(x)$?
• What is the horizontal asymptote of $f(x)$?
1. **State the problem:**
We need to analyze and graph the exponential function $$f(x) = -6\left(\frac{4}{3}\right)^x$$ and answer questions about its behavior.
2. **Recall the general form and properties:**
An exponential function has the form $$f(x) = a b^x$$ where $a$ is a constant and $b > 0$ is the base.
- If $a < 0$ and $b > 1$, the function is decreasing.
- The domain of any exponential function is all real numbers: $$(-\infty, \infty)$$.
- The range depends on $a$; since $a$ is negative, the function values will be negative.
- The horizontal asymptote is $y=0$.
3. **Determine if the function is increasing or decreasing:**
Since $a = -6 < 0$ and $b = \frac{4}{3} > 1$, the function is **decreasing**.
4. **Find the domain and range:**
- Domain: $$(-\infty, \infty)$$ because exponential functions are defined for all real $x$.
- Range: Since $a$ is negative, the function outputs negative values only, so the range is $$(-\infty, 0)$$.
5. **Find the y-intercept:**
The y-intercept occurs at $x=0$:
$$f(0) = -6\left(\frac{4}{3}\right)^0 = -6 \times 1 = -6$$
6. **Find the horizontal asymptote:**
As $x \to \infty$, $$\left(\frac{4}{3}\right)^x \to \infty$$, but multiplied by $-6$ it goes to $-\infty$.
As $x \to -\infty$, $$\left(\frac{4}{3}\right)^x \to 0^+$$, so $$f(x) \to -6 \times 0 = 0$$ from below.
Thus, the horizontal asymptote is $$y = 0$$.
7. **Summary:**
- The function is decreasing.
- Domain: $$(-\infty, \infty)$$.
- Range: $$(-\infty, 0)$$.
- Y-intercept: $-6$.
- Horizontal asymptote: $y=0$.
8. **Graph shape:**
The graph is an exponential decay curve below the x-axis, approaching $y=0$ from below on the left and decreasing without bound on the right.