Question: b.) y = C1e^x + C2e^2x + C3e^3x
1. **State the problem:**
We are given the function $$y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}$$ and asked to express it by isolation, which means solving for one of the constants or terms if possible.
2. **Understanding the function:**
This is a linear combination of exponential functions with different exponents. Each term is independent, so isolating one term means expressing it in terms of $$y$$ and the other terms.
3. **Isolate a term, for example, $$C_1 e^x$$:**
$$C_1 e^x = y - C_2 e^{2x} - C_3 e^{3x}$$
4. **Similarly, isolate $$C_2 e^{2x}$$:**
$$C_2 e^{2x} = y - C_1 e^x - C_3 e^{3x}$$
5. **Or isolate $$C_3 e^{3x}$$:**
$$C_3 e^{3x} = y - C_1 e^x - C_2 e^{2x}$$
6. **Summary:**
Isolating any term involves subtracting the other terms from $$y$$. This is straightforward because the function is a sum of independent exponential terms.
**Final isolated forms:**
$$y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}$$
$$C_1 e^x = y - C_2 e^{2x} - C_3 e^{3x}$$
$$C_2 e^{2x} = y - C_1 e^x - C_3 e^{3x}$$
$$C_3 e^{3x} = y - C_1 e^x - C_2 e^{2x}$$