Question: The expression 4 (7x² + 6x + 6) - 6 (7x² + 2x + 6) equals
[blank] x² + [blank] x + [blank]
position_hint=top-left
1. **State the problem:** Simplify the expression $4 (7x^2 + 6x + 6) - 6 (7x^2 + 2x + 6)$ and write it in the form $ax^2 + bx + c$.
2. **Apply the distributive property:** Multiply each term inside the parentheses by the factor outside.
$$4 (7x^2 + 6x + 6) = 4 \times 7x^2 + 4 \times 6x + 4 \times 6 = 28x^2 + 24x + 24$$
$$-6 (7x^2 + 2x + 6) = -6 \times 7x^2 - 6 \times 2x - 6 \times 6 = -42x^2 - 12x - 36$$
3. **Combine like terms:** Add the corresponding coefficients of $x^2$, $x$, and the constant terms.
$$28x^2 + 24x + 24 - 42x^2 - 12x - 36 = (28x^2 - 42x^2) + (24x - 12x) + (24 - 36)$$
4. **Simplify each group:**
$$28x^2 - 42x^2 = \cancel{28}x^2 - \cancel{42}x^2 = -14x^2$$
$$24x - 12x = \cancel{24}x - \cancel{12}x = 12x$$
$$24 - 36 = -12$$
5. **Write the final simplified expression:**
$$-14x^2 + 12x - 12$$
**Answer:** The expression equals $-14x^2 + 12x - 12$.