Question: Factor completely. $x^2 - 64$
1. **State the problem:** Factor the expression $$x^2 - 64$$ completely.
2. **Recognize the formula:** This is a difference of squares, which follows the formula $$a^2 - b^2 = (a - b)(a + b)$$.
3. **Identify terms:** Here, $$a = x$$ and $$b = 8$$ because $$64 = 8^2$$.
4. **Apply the formula:**
$$x^2 - 64 = (x - 8)(x + 8)$$
5. **Final answer:** The completely factored form is $$(x - 8)(x + 8)$$.