Question: Factor completely over the integers. $x^4 - 4x^2 - 5$
1. **State the problem:** Factor the polynomial $$x^4 - 4x^2 - 5$$ completely over the integers.
2. **Recognize the form:** Notice that the polynomial is a quadratic in terms of $x^2$. Let $y = x^2$, then the expression becomes $$y^2 - 4y - 5$$.
3. **Factor the quadratic in $y$:** We look for two numbers that multiply to $-5$ and add to $-4$. These numbers are $-5$ and $1$.
4. **Write the factorization in $y$:**
$$y^2 - 4y - 5 = (y - 5)(y + 1)$$
5. **Substitute back $y = x^2$:**
$$(x^2 - 5)(x^2 + 1)$$
6. **Check for further factorization:**
- $x^2 - 5$ cannot be factored further over the integers because $5$ is not a perfect square.
- $x^2 + 1$ cannot be factored over the integers because it has no real roots.
7. **Final factorization:**
$$\boxed{(x^2 - 5)(x^2 + 1)}$$