Question: Write the following expression in factored form.
$x^2 - 7x + 10$
$(x - 1)(x + 10)$
$(x + 1)(x - 10)$
$(x + 2)(x + 5)$
$(x - 2)(x - 5)$
1. **State the problem:** We need to factor the quadratic expression $$x^2 - 7x + 10$$ into the product of two binomials.
2. **Recall the factoring formula:** For a quadratic expression $$ax^2 + bx + c$$, if $a=1$, we look for two numbers that multiply to $c$ and add to $b$.
3. **Identify $a$, $b$, and $c$:** Here, $a=1$, $b=-7$, and $c=10$.
4. **Find two numbers that multiply to $10$ and add to $-7$:** The pairs of factors of $10$ are $(1, 10)$ and $(2, 5)$. Since the sum must be $-7$, and the product positive, both numbers must be negative: $-2$ and $-5$.
5. **Write the factored form:** Using these numbers, the factorization is $$(x - 2)(x - 5)$$.
6. **Verify by expansion:**
$$
(x - 2)(x - 5) = x^2 - 5x - 2x + 10 = x^2 - 7x + 10
$$
This matches the original expression.
**Final answer:** $$(x - 2)(x - 5)$$