Question: x² + 14x + 49
FACTOR OUT OF THE FF
1. **State the problem:** Factor the quadratic expression $$x^2 + 14x + 49$$.
2. **Recall the factoring formula:** For a quadratic expression $$ax^2 + bx + c$$, if it can be factored into the form $$(x + m)(x + n)$$, then $$m + n = b$$ and $$mn = c$$.
3. **Identify coefficients:** Here, $$a = 1$$, $$b = 14$$, and $$c = 49$$.
4. **Find two numbers that add to $$b$$ and multiply to $$c$$:** We need $$m$$ and $$n$$ such that $$m + n = 14$$ and $$mn = 49$$.
5. **Check factors of 49:** The pairs are (1, 49), (7, 7), (-1, -49), (-7, -7). Only (7, 7) add to 14.
6. **Write the factored form:** $$x^2 + 14x + 49 = (x + 7)(x + 7) = (x + 7)^2$$.
7. **Final answer:** The factored form is $$\boxed{(x + 7)^2}$$.