Factor Quadratic Ff8E2C

1. **State the problem:** Factor the quadratic expression $$x^2 + 6x + 9$$. 2. **Recall the formula:** A quadratic expression of the form $$ax^2 + bx + c$$ can be factored by finding two numbers that multiply to $$ac$$ and add to $$b$$. 3. **Identify coefficients:** Here, $$a = 1$$, $$b = 6$$, and $$c = 9$$. 4. **Find two numbers:** We need two numbers that multiply to $$1 \times 9 = 9$$ and add to $$6$$. These numbers are $$3$$ and $$3$$. 5. **Rewrite the middle term:** $$x^2 + 3x + 3x + 9$$. 6. **Group terms:** $$(x^2 + 3x) + (3x + 9)$$. 7. **Factor each group:** $$x(x + 3) + 3(x + 3)$$. 8. **Factor out the common binomial:** $$(x + 3)(x + 3)$$ or $$(x + 3)^2$$. **Final answer:** $$x^2 + 6x + 9 = (x + 3)^2$$.