Question: Factors of the number $36$
1. **State the problem:** Find all factors of the number $36$.
2. **Recall the definition:** Factors of a number are integers that divide the number exactly without leaving a remainder.
3. **Start with $1$ and the number itself:** $1$ and $36$ are always factors.
4. **Check integers from $2$ up to $\sqrt{36} = 6$:**
- $2$ divides $36$ since $36 \div 2 = 18$ (no remainder), so $2$ and $18$ are factors.
- $3$ divides $36$ since $36 \div 3 = 12$, so $3$ and $12$ are factors.
- $4$ divides $36$ since $36 \div 4 = 9$, so $4$ and $9$ are factors.
- $5$ does not divide $36$ exactly.
- $6$ divides $36$ since $36 \div 6 = 6$, so $6$ is a factor (counted once since $6 \times 6 = 36$).
5. **List all factors found:** $1, 2, 3, 4, 6, 9, 12, 18, 36$.
6. **Final answer:** The factors of $36$ are $\boxed{1, 2, 3, 4, 6, 9, 12, 18, 36}$.