Question: If $A \times B = C$
$C + C + C + C + C = 60$
$B + B + B = 18$
What is the value of $A$?
1. **State the problem:** We are given the equations $A \times B = C$, $C + C + C + C + C = 60$, and $B + B + B = 18$. We need to find the value of $A$.
2. **Rewrite the sums as multiplications:**
- $C + C + C + C + C = 5C = 60$
- $B + B + B = 3B = 18$
3. **Solve for $C$ and $B$:**
- $5C = 60 \implies C = \frac{60}{5} = 12$
- $3B = 18 \implies B = \frac{18}{3} = 6$
4. **Use the equation $A \times B = C$ to find $A$:**
- Substitute $B = 6$ and $C = 12$:
$$A \times 6 = 12$$
5. **Solve for $A$:**
$$A = \frac{12}{6}$$
$$A = \cancel{\frac{12}{6}} 2$$
6. **Final answer:**
The value of $A$ is $2$.