Question: The point with coordinates $(d, 4)$ lies on the line shown. What is the value of $d$?
1. **State the problem:** We need to find the value of $d$ such that the point $(d, 4)$ lies on the line passing through $(0,7)$ and $(8,0)$.
2. **Find the equation of the line:** The slope $m$ of the line is given by $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 7}{8 - 0} = \frac{-7}{8}.$$
3. Using point-slope form with point $(0,7)$: $$y - 7 = m(x - 0) \implies y - 7 = -\frac{7}{8}x.$$
4. Simplify to slope-intercept form: $$y = 7 - \frac{7}{8}x.$$
5. Substitute $y = 4$ to find $d$: $$4 = 7 - \frac{7}{8}d.$$
6. Rearrange to isolate $d$: $$4 - 7 = -\frac{7}{8}d \implies -3 = -\frac{7}{8}d.$$
7. Multiply both sides by $-\frac{8}{7}$ to solve for $d$: $$d = -3 \times \left(-\frac{8}{7}\right) = \frac{24}{7}.$$
8. **Answer:** The value of $d$ is $$\boxed{\frac{24}{7}}.$$