Question: 8. 5/3 + 4/9 + 6/18
9. 5/4 + 7/8 + 1/16
10. 5/8 - 1/4
11. 5/12 - 7/24
1. We are asked to perform addition and subtraction of fractions for four separate problems.
2. The general formula for adding or subtracting fractions is $$\frac{a}{b} \pm \frac{c}{d} = \frac{ad \pm bc}{bd}$$ where $a,b,c,d$ are integers and $b,d \neq 0$.
3. Important rules:
- Find a common denominator (usually the least common denominator).
- Convert each fraction to an equivalent fraction with the common denominator.
- Add or subtract the numerators.
- Simplify the resulting fraction if possible.
**Problem 8:** $$\frac{5}{3} + \frac{4}{9} + \frac{6}{18}$$
4. Find the least common denominator (LCD) of 3, 9, and 18.
- $\mathrm{LCD}(3,9,18) = 18$
5. Convert each fraction:
- $$\frac{5}{3} = \frac{5 \times 6}{3 \times 6} = \frac{30}{18}$$
- $$\frac{4}{9} = \frac{4 \times 2}{9 \times 2} = \frac{8}{18}$$
- $$\frac{6}{18}$$ is already with denominator 18.
6. Add the numerators:
- $$\frac{30}{18} + \frac{8}{18} + \frac{6}{18} = \frac{30 + 8 + 6}{18} = \frac{44}{18}$$
7. Simplify $$\frac{44}{18}$$:
- Both numerator and denominator divisible by 2.
- $$\frac{44}{18} = \frac{\cancel{44}^{22}}{\cancel{18}^{9}} = \frac{22}{9}$$
**Problem 9:** $$\frac{5}{4} + \frac{7}{8} + \frac{1}{16}$$
8. Find LCD of 4, 8, and 16.
- $\mathrm{LCD}(4,8,16) = 16$
9. Convert each fraction:
- $$\frac{5}{4} = \frac{5 \times 4}{4 \times 4} = \frac{20}{16}$$
- $$\frac{7}{8} = \frac{7 \times 2}{8 \times 2} = \frac{14}{16}$$
- $$\frac{1}{16}$$ already has denominator 16.
10. Add numerators:
- $$\frac{20}{16} + \frac{14}{16} + \frac{1}{16} = \frac{20 + 14 + 1}{16} = \frac{35}{16}$$
11. $$\frac{35}{16}$$ is an improper fraction and cannot be simplified further.
**Problem 10:** $$\frac{5}{8} - \frac{1}{4}$$
12. Find LCD of 8 and 4.
- $\mathrm{LCD}(8,4) = 8$
13. Convert $$\frac{1}{4}$$ to denominator 8:
- $$\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$$
14. Subtract numerators:
- $$\frac{5}{8} - \frac{2}{8} = \frac{5 - 2}{8} = \frac{3}{8}$$
**Problem 11:** $$\frac{5}{12} - \frac{7}{24}$$
15. Find LCD of 12 and 24.
- $\mathrm{LCD}(12,24) = 24$
16. Convert $$\frac{5}{12}$$ to denominator 24:
- $$\frac{5}{12} = \frac{5 \times 2}{12 \times 2} = \frac{10}{24}$$
17. Subtract numerators:
- $$\frac{10}{24} - \frac{7}{24} = \frac{10 - 7}{24} = \frac{3}{24}$$
18. Simplify $$\frac{3}{24}$$:
- Both divisible by 3.
- $$\frac{3}{24} = \frac{\cancel{3}^{1}}{\cancel{24}^{8}} = \frac{1}{8}$$
**Final answers:**
- Problem 8: $$\frac{22}{9}$$
- Problem 9: $$\frac{35}{16}$$
- Problem 10: $$\frac{3}{8}$$
- Problem 11: $$\frac{1}{8}$$