Subjects algebra

Fraction Simplification 370Fb6

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Question: ALD R.iN R. C@pC14 153 -math 1. 6 12 2. 28 12 3. 13 7 4. 4 8 5. 16 25 6. 16 24 position_hint: top-left position_hint: top-right position_hint: center position_hint: bottom-left position_hint: bottom-right
1. **Stating the problem:** Simplify the fraction $$\frac{6}{12}$$. 2. **Formula and rules:** To simplify a fraction, divide numerator and denominator by their greatest common divisor (GCD). 3. **Find GCD:** GCD of 6 and 12 is 6. 4. **Divide numerator and denominator:** $$\frac{6}{12} = \frac{\cancel{6}^1}{\cancel{6}^2} = \frac{1}{2}$$ 5. **Final answer:** $$\frac{1}{2}$$. --- 1. **Stating the problem:** Simplify the fraction $$\frac{28}{12}$$. 2. **Formula and rules:** Divide numerator and denominator by their GCD. 3. **Find GCD:** GCD of 28 and 12 is 4. 4. **Divide numerator and denominator:** $$\frac{28}{12} = \frac{\cancel{4}^7}{\cancel{4}^3} = \frac{7}{3}$$ 5. **Final answer:** $$\frac{7}{3}$$. --- 1. **Stating the problem:** Simplify the fraction $$\frac{13}{7}$$. 2. **Formula and rules:** Check if numerator and denominator have common factors. 3. **GCD:** 13 and 7 are both prime and have no common factors except 1. 4. **Fraction is already simplified:** $$\frac{13}{7}$$. 5. **Final answer:** $$\frac{13}{7}$$. --- 1. **Stating the problem:** Simplify the fraction $$\frac{4}{8}$$. 2. **Formula and rules:** Divide numerator and denominator by their GCD. 3. **Find GCD:** GCD of 4 and 8 is 4. 4. **Divide numerator and denominator:** $$\frac{4}{8} = \frac{\cancel{4}^1}{\cancel{4}^2} = \frac{1}{2}$$ 5. **Final answer:** $$\frac{1}{2}$$. --- 1. **Stating the problem:** Simplify the fraction $$\frac{16}{25}$$. 2. **Formula and rules:** Divide numerator and denominator by their GCD. 3. **Find GCD:** 16 and 25 have no common factors except 1. 4. **Fraction is already simplified:** $$\frac{16}{25}$$. 5. **Final answer:** $$\frac{16}{25}$$. --- 1. **Stating the problem:** Simplify the fraction $$\frac{16}{24}$$. 2. **Formula and rules:** Divide numerator and denominator by their GCD. 3. **Find GCD:** GCD of 16 and 24 is 8. 4. **Divide numerator and denominator:** $$\frac{16}{24} = \frac{\cancel{8}^2}{\cancel{8}^3} = \frac{2}{3}$$ 5. **Final answer:** $$\frac{2}{3}$$.