Question: ALD R.iN R. C@pC14
153 -math
1. 6
12
2. 28
12
3. 13
7
4. 4
8
5. 16
25
6. 16
24
position_hint: top-left
position_hint: top-right
position_hint: center
position_hint: bottom-left
position_hint: bottom-right
1. **Stating the problem:** Simplify the fraction $$\frac{6}{12}$$.
2. **Formula and rules:** To simplify a fraction, divide numerator and denominator by their greatest common divisor (GCD).
3. **Find GCD:** GCD of 6 and 12 is 6.
4. **Divide numerator and denominator:**
$$\frac{6}{12} = \frac{\cancel{6}^1}{\cancel{6}^2} = \frac{1}{2}$$
5. **Final answer:** $$\frac{1}{2}$$.
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1. **Stating the problem:** Simplify the fraction $$\frac{28}{12}$$.
2. **Formula and rules:** Divide numerator and denominator by their GCD.
3. **Find GCD:** GCD of 28 and 12 is 4.
4. **Divide numerator and denominator:**
$$\frac{28}{12} = \frac{\cancel{4}^7}{\cancel{4}^3} = \frac{7}{3}$$
5. **Final answer:** $$\frac{7}{3}$$.
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1. **Stating the problem:** Simplify the fraction $$\frac{13}{7}$$.
2. **Formula and rules:** Check if numerator and denominator have common factors.
3. **GCD:** 13 and 7 are both prime and have no common factors except 1.
4. **Fraction is already simplified:** $$\frac{13}{7}$$.
5. **Final answer:** $$\frac{13}{7}$$.
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1. **Stating the problem:** Simplify the fraction $$\frac{4}{8}$$.
2. **Formula and rules:** Divide numerator and denominator by their GCD.
3. **Find GCD:** GCD of 4 and 8 is 4.
4. **Divide numerator and denominator:**
$$\frac{4}{8} = \frac{\cancel{4}^1}{\cancel{4}^2} = \frac{1}{2}$$
5. **Final answer:** $$\frac{1}{2}$$.
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1. **Stating the problem:** Simplify the fraction $$\frac{16}{25}$$.
2. **Formula and rules:** Divide numerator and denominator by their GCD.
3. **Find GCD:** 16 and 25 have no common factors except 1.
4. **Fraction is already simplified:** $$\frac{16}{25}$$.
5. **Final answer:** $$\frac{16}{25}$$.
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1. **Stating the problem:** Simplify the fraction $$\frac{16}{24}$$.
2. **Formula and rules:** Divide numerator and denominator by their GCD.
3. **Find GCD:** GCD of 16 and 24 is 8.
4. **Divide numerator and denominator:**
$$\frac{16}{24} = \frac{\cancel{8}^2}{\cancel{8}^3} = \frac{2}{3}$$
5. **Final answer:** $$\frac{2}{3}$$.