Question: Graph the following functions to find the value(s) of $x$ for which $f(x)=g(x)$. $f(x)= \frac{x-2}{-2}$, $g(x)=-4x+24$
1. **State the problem:** We need to find the value(s) of $x$ such that $f(x) = g(x)$ where $f(x) = \frac{x-2}{-2}$ and $g(x) = -4x + 24$.
2. **Set the functions equal:** To find $x$ where $f(x) = g(x)$, solve:
$$\frac{x-2}{-2} = -4x + 24$$
3. **Multiply both sides by $-2$ to clear the denominator:**
$$x - 2 = (-2)(-4x + 24)$$
$$x - 2 = 8x - 48$$
4. **Bring all terms to one side:**
$$x - 2 - 8x + 48 = 0$$
$$-7x + 46 = 0$$
5. **Solve for $x$:**
$$-7x = -46$$
$$x = \frac{-46}{-7}$$
$$x = \frac{46}{7}$$
6. **Interpretation:** The functions $f(x)$ and $g(x)$ intersect at $x = \frac{46}{7} \approx 6.57$.
7. **Verify by substitution:**
$$f\left(\frac{46}{7}\right) = \frac{\frac{46}{7} - 2}{-2} = \frac{\frac{46}{7} - \frac{14}{7}}{-2} = \frac{\frac{32}{7}}{-2} = \frac{32}{7} \times \left(-\frac{1}{2}\right) = -\frac{16}{7}$$
$$g\left(\frac{46}{7}\right) = -4 \times \frac{46}{7} + 24 = -\frac{184}{7} + \frac{168}{7} = -\frac{16}{7}$$
Both values match, confirming the solution.
**Final answer:**
$$x = \frac{46}{7}$$