Question: Find each function value, if it exists.
f(t) = \sqrt{t^2 + 1}
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. f(0) = __ (Simplify your answer. Type an exact answer, using radicals as needed)
B. The square root is not a real number.
top-left: f(t) = \sqrt{t^2 + 1} and the question asks for f(0); no graph is shown.
1. **State the problem:** We need to find the value of the function $$f(t) = \sqrt{t^2 + 1}$$ at $$t=0$$.
2. **Write the formula:** $$f(t) = \sqrt{t^2 + 1}$$.
3. **Substitute the value:** Replace $$t$$ with $$0$$:
$$f(0) = \sqrt{0^2 + 1}$$
4. **Simplify inside the square root:**
$$f(0) = \sqrt{0 + 1} = \sqrt{1}$$
5. **Evaluate the square root:**
$$f(0) = 1$$
6. **Conclusion:** The value of $$f(0)$$ is $$1$$, which is a real number.
Therefore, the correct choice is A: $$f(0) = 1$$.