Function Values C5D79D

1. **State the problem:** We need to find the values of the function $$f(x) = \frac{1}{2}x$$ at $$x=0$$, $$x=2$$, and $$x=-2$$. 2. **Formula:** The function is given by $$f(x) = \frac{1}{2}x$$. This means to find $$f(a)$$ for some number $$a$$, we multiply $$a$$ by $$\frac{1}{2}$$. 3. **Calculate each value:** a. For $$x=0$$: $$f(0) = \frac{1}{2} \times 0 = 0$$ b. For $$x=2$$: $$f(2) = \frac{1}{2} \times 2 = \frac{\cancel{2}}{2} \times \cancel{1} = 1$$ c. For $$x=-2$$: $$f(-2) = \frac{1}{2} \times (-2) = \frac{\cancel{2}}{2} \times (-\cancel{1}) = -1$$ 4. **Final answers:** a. $$f(0) = 0$$ b. $$f(2) = 1$$ c. $$f(-2) = -1$$ This shows how to evaluate the function at different points by multiplying the input by $$\frac{1}{2}$$.