Subjects algebra

Function Values Ebcc2B

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Question: Complete the table of values for the functions $f(x) = |x - 3| - 4$ and $g(x) = 3^x - 5$. Write your answers as whole numbers, decimals, or simplified fractions or mixed numbers. $x \quad f(x) \quad g(x)$ $0 \quad -1 \quad -4$ $1$ $2 \quad -3 \quad 4$ $3$ $4 Based on the values in the table, where does the equation $f(x) = g(x)$ have a solution? $x = 1$ between $x = 1$ and $x = 2$ $x = 2$ between $x = 2$ and $x = 3$
1. **State the problem:** We need to complete the table for $f(x) = |x - 3| - 4$ and $g(x) = 3^x - 5$ at $x = 1, 3, 4$ and determine where $f(x) = g(x)$ has a solution. 2. **Calculate $f(x)$ values:** - For $x=1$: $$f(1) = |1 - 3| - 4 = | -2 | - 4 = 2 - 4 = -2$$ - For $x=3$: $$f(3) = |3 - 3| - 4 = 0 - 4 = -4$$ - For $x=4$: $$f(4) = |4 - 3| - 4 = 1 - 4 = -3$$ 3. **Calculate $g(x)$ values:** - For $x=1$: $$g(1) = 3^1 - 5 = 3 - 5 = -2$$ - For $x=3$: $$g(3) = 3^3 - 5 = 27 - 5 = 22$$ - For $x=4$: $$g(4) = 3^4 - 5 = 81 - 5 = 76$$ 4. **Complete the table:** \begin{tabular}{c|c|c} $x$ & $f(x)$ & $g(x)$ \\ \hline 0 & -1 & -4 \\ 1 & -2 & -2 \\ 2 & -3 & 4 \\ 3 & -4 & 22 \\ 4 & -3 & 76 \\ \end{tabular} 5. **Determine where $f(x) = g(x)$:** - At $x=1$, $f(1) = -2$ and $g(1) = -2$, so $f(1) = g(1)$. - Between $x=1$ and $x=2$, $f(x)$ decreases from $-2$ to $-3$, $g(x)$ increases from $-2$ to $4$, so they are not equal in between. - At $x=2$, $f(2) = -3$ and $g(2) = 4$, not equal. - Between $x=2$ and $x=3$, $f(x)$ decreases from $-3$ to $-4$, $g(x)$ increases from $4$ to $22$, no equality. **Final answer:** The equation $f(x) = g(x)$ has a solution at $x = 1$.