1. **State the problem:** Simplify the expression $$\frac{50\left(1-0.8^{8-1}\right)}{\left(1-0.8\right)}$$.
2. **Identify the formula:** This expression resembles the sum of a geometric series formula $$S_n = a \frac{1-r^n}{1-r}$$ where $a=50$, $r=0.8$, and $n=8-1=7$.
3. **Calculate the power:** Compute $0.8^{7}$.
$$0.8^{7} = 0.2097152$$
4. **Substitute the value:**
$$1 - 0.8^{7} = 1 - 0.2097152 = 0.7902848$$
5. **Calculate the denominator:**
$$1 - 0.8 = 0.2$$
6. **Substitute all values back into the expression:**
$$\frac{50 \times 0.7902848}{0.2}$$
7. **Multiply numerator:**
$$50 \times 0.7902848 = 39.51424$$
8. **Divide by denominator:**
$$\frac{39.51424}{0.2} = 197.5712$$
**Final answer:**
$$197.5712$$
Geometric Series Sum D942F2
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