Graph Linear 64C3C7

1. **State the problem:** We need to graph the linear equation $$-4x - 5y = 40$$. 2. **Rewrite the equation in slope-intercept form:** The slope-intercept form is $$y = mx + b$$, where $$m$$ is the slope and $$b$$ is the y-intercept. 3. **Isolate $$y$$:** $$-4x - 5y = 40$$ Add $$4x$$ to both sides: $$-5y = 4x + 40$$ Divide both sides by $$-5$$: $$y = \frac{4x + 40}{-5} = \frac{4x}{-5} + \frac{40}{-5} = -\frac{4}{5}x - 8$$ 4. **Identify slope and intercept:** Slope $$m = -\frac{4}{5}$$ Y-intercept $$b = -8$$ 5. **Find x-intercept:** Set $$y=0$$ and solve for $$x$$: $$-4x - 5(0) = 40 \Rightarrow -4x = 40 \Rightarrow x = \frac{40}{-4} = -10$$ 6. **Plot points:** - Y-intercept at $$(0, -8)$$ - X-intercept at $$(-10, 0)$$ 7. **Draw the line through these points:** This line represents the graph of the equation. **Final answer:** The graph is a line with slope $$-\frac{4}{5}$$ passing through points $$(0, -8)$$ and $$(-10, 0)$$.