Subjects algebra

Improper Fractions Df4B2A

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Question: a) $\frac{17}{4}$ = The whole number is The numerator is The denominator is b) $\frac{22}{3}$ = The whole number is The numerator is The denominator is
1. **State the problem:** We need to express the improper fractions $\frac{17}{4}$ and $\frac{22}{3}$ as mixed numbers and identify their whole number, numerator, and denominator parts. 2. **Recall the formula:** An improper fraction $\frac{a}{b}$ can be written as a mixed number $c \frac{d}{b}$ where: - $c = \left\lfloor \frac{a}{b} \right\rfloor$ (the whole number part) - $d = a - b \times c$ (the new numerator) - $b$ remains the denominator 3. **Solve for $\frac{17}{4}$:** - Divide $17$ by $4$: $17 \div 4 = 4$ remainder $1$ - So, whole number $c = 4$ - New numerator $d = 17 - 4 \times 4 = 17 - 16 = 1$ - Denominator remains $4$ - Mixed number: $4 \frac{1}{4}$ 4. **Solve for $\frac{22}{3}$:** - Divide $22$ by $3$: $22 \div 3 = 7$ remainder $1$ - Whole number $c = 7$ - New numerator $d = 22 - 3 \times 7 = 22 - 21 = 1$ - Denominator remains $3$ - Mixed number: $7 \frac{1}{3}$ **Final answers:** - For $\frac{17}{4}$: - Whole number: $4$ - Numerator: $1$ - Denominator: $4$ - For $\frac{22}{3}$: - Whole number: $7$ - Numerator: $1$ - Denominator: $3$