Inequality Interval 1Ec968

1. **State the problem:** We need to find which inequality corresponds to the solution set $[6, +\infty)$, meaning all $x$ values starting at 6 and going to infinity. 2. **Analyze each option:** - a. $x \geq 6$ or $x > 10$ means $x$ is at least 6 or greater than 10. Since $x \geq 6$ already covers $[6, +\infty)$, this option matches. - b. $x \geq 6$ or $x < 11$ means all $x$ greater or equal to 6 or less than 11. This covers all real numbers because $x < 11$ includes numbers less than 6, so the solution is $(-\infty, +\infty)$, not $[6, +\infty)$. - c. $x \leq 6$ or $x \geq 0$ means all $x$ less or equal to 6 or greater or equal to 0, which covers all real numbers again. - d. $6 \leq x \leq 100,000$ means $x$ is between 6 and 100,000 inclusive, which is a bounded interval, not $[6, +\infty)$. 3. **Conclusion:** Only option a matches the solution set $[6, +\infty)$. **Final answer:** a. $x \geq 6$ or $x > 10$