Inequality Solve 180040

1. **State the problem:** Solve the inequality $$\frac{x}{3} + 1 > 4$$. 2. **Isolate the variable term:** Subtract 1 from both sides: $$\frac{x}{3} + 1 - 1 > 4 - 1$$ $$\frac{x}{3} > 3$$ 3. **Eliminate the denominator:** Multiply both sides by 3 (positive number, so inequality direction stays the same): $$3 \times \frac{x}{3} > 3 \times 3$$ $$\cancel{3} \times \frac{x}{\cancel{3}} > 9$$ $$x > 9$$ 4. **Final answer:** The solution to the inequality is $$x > 9$$. This means any number greater than 9 satisfies the original inequality.