Question: Solve the inequality and graph the solution on the line provided.
minus, 18, plus, 3, x, is less than or equal to, 0
−18+3x≤0
1. **State the problem:** Solve the inequality $$-18 + 3x \leq 0$$.
2. **Isolate the variable term:** Add 18 to both sides:
$$-18 + 3x + 18 \leq 0 + 18$$
which simplifies to
$$3x \leq 18$$.
3. **Divide both sides by 3:**
$$\frac{\cancel{3}x}{\cancel{3}} \leq \frac{18}{3}$$
which simplifies to
$$x \leq 6$$.
4. **Interpretation:** The solution to the inequality is all values of $$x$$ less than or equal to $$6$$.
5. **Graphing on the number line:**
- Draw a solid circle at $$6$$ to indicate $$x$$ can equal $$6$$.
- Shade the line to the left of $$6$$ to show all values less than $$6$$ are included.
**Final answer:** $$x \leq 6$$.