Subjects algebra

Intercepts Cubic 04D40A

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Question: how to find x and y intercepts of y=-(x+2)^3
1. **State the problem:** Find the $x$-intercepts and $y$-intercepts of the function $$y=-(x+2)^3$$. 2. **Recall the definitions:** - The $x$-intercepts occur where $$y=0$$. - The $y$-intercept occurs where $$x=0$$. 3. **Find the $x$-intercepts:** Set $$y=0$$: $$0 = -(x+2)^3$$ This implies: $$(x+2)^3 = 0$$ Take the cube root of both sides: $$x+2 = 0$$ Solve for $$x$$: $$x = -2$$ 4. **Find the $y$-intercept:** Set $$x=0$$ in the original equation: $$y = -(0+2)^3 = -2^3 = -8$$ 5. **Summary:** - The $x$-intercept is at $$(-2, 0)$$. - The $y$-intercept is at $$(0, -8)$$. These points show where the graph crosses the axes.