Question: User: f(x)=10-x; f^-1(x)=
1. **State the problem:** Find the inverse function $$f^{-1}(x)$$ of the function $$f(x) = 10 - x$$.
2. **Recall the definition of inverse function:** The inverse function $$f^{-1}(x)$$ satisfies $$f(f^{-1}(x)) = x$$.
3. **Start with the equation:** $$y = 10 - x$$.
4. **Swap variables:** Replace $$y$$ with $$x$$ and $$x$$ with $$y$$ to find the inverse:
$$x = 10 - y$$.
5. **Solve for $$y$$:**
$$y = 10 - x$$.
6. **Therefore, the inverse function is:**
$$f^{-1}(x) = 10 - x$$.
7. **Check:**
$$f(f^{-1}(x)) = f(10 - x) = 10 - (10 - x) = x$$, confirming the inverse is correct.
**Final answer:** $$f^{-1}(x) = 10 - x$$.