Question: A farmer has 3000 feet of fencing to enclose a rectangular plot that borders a river. What is the largest area that can be enclosed?
1. **State the problem:**
A farmer wants to enclose a rectangular plot next to a river using 3000 feet of fencing. Since the river forms one side, fencing is needed for only three sides.
2. **Define variables:**
Let $x$ be the length of the side parallel to the river (no fencing needed on the river side).
Let $y$ be the length of each of the two other sides perpendicular to the river.
3. **Write the fencing constraint:**
Since the river side needs no fence, the total fencing used is for two sides of length $y$ and one side of length $x$:
$$2y + x = 3000$$
4. **Express $x$ in terms of $y$:**
$$x = 3000 - 2y$$
5. **Write the area function:**
The area $A$ of the rectangle is:
$$A = x \times y$$
Substitute $x$:
$$A = (3000 - 2y) y = 3000y - 2y^2$$
6. **Maximize the area:**
To find the maximum area, take the derivative of $A$ with respect to $y$ and set it to zero:
$$\frac{dA}{dy} = 3000 - 4y = 0$$
7. **Solve for $y$:**
$$3000 - 4y = 0 \implies 4y = 3000 \implies y = \frac{3000}{4} = 750$$
8. **Find $x$ using $y=750$:**
$$x = 3000 - 2(750) = 3000 - 1500 = 1500$$
9. **Calculate the maximum area:**
$$A = x \times y = 1500 \times 750 = 1125000$$
10. **Conclusion:**
The largest area that can be enclosed is $$1125000$$ square feet when the side parallel to the river is $$1500$$ feet and the other two sides are each $$750$$ feet.