Subjects algebra

Library Book Growth 798Cea

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Question: Suppose that a library contains $12,000$ books now, and adds $250$ books every month. (a) Write an explicit formula for a linear model that describes this growth. $P_n =$ (b) If this trend continues, how many books will the library contain in a year? books (c) How long will it be before the library contains $19,000$ books? Round to the nearest month. months
1. **State the problem:** We have a library with an initial number of books $12,000$ and it adds $250$ books every month. We want to model this growth linearly. 2. **Write the explicit formula:** The general formula for linear growth is: $$P_n = P_0 + dn$$ where: - $P_n$ is the number of books after $n$ months, - $P_0$ is the initial number of books, - $d$ is the monthly increase, - $n$ is the number of months. Given $P_0 = 12,000$ and $d = 250$, the formula is: $$P_n = 12,000 + 250n$$ 3. **Calculate the number of books after 1 year (12 months):** Substitute $n = 12$: $$P_{12} = 12,000 + 250 \times 12$$ $$P_{12} = 12,000 + 3,000 = 15,000$$ So, after 1 year, the library will have $15,000$ books. 4. **Find how long until the library has $19,000$ books:** Set $P_n = 19,000$ and solve for $n$: $$19,000 = 12,000 + 250n$$ Subtract $12,000$ from both sides: $$19,000 - 12,000 = 250n$$ $$7,000 = 250n$$ Divide both sides by $250$: $$n = \frac{7,000}{250}$$ Show cancellation: $$n = \frac{\cancel{7,000}}{\cancel{250}} = 28$$ So, it will take $28$ months for the library to have $19,000$ books. **Final answers:** (a) $$P_n = 12,000 + 250n$$ (b) After 1 year, the library will have $15,000$ books. (c) It will take $28$ months to reach $19,000$ books.