Subjects algebra

Line Equation Ae05B9

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Question: Write the equation of the line in fully simplified slope-intercept form. Graph: a rising straight line passes through points $(0, -2)$, $(1, 0)$, $(2, 2)$, $(3, 4)$, $(4, 6)$, $(5, 8)$, $(6, 10)$, with arrows extending to the bottom-left and top-right; position_hint = center.
1. **State the problem:** Find the equation of the line passing through the points given, in slope-intercept form $y=mx+b$. 2. **Identify points:** We have points $(0,-2)$ and $(1,0)$ among others. 3. **Calculate the slope $m$:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - (-2)}{1 - 0} = \frac{2}{1} = 2$$ 4. **Use slope-intercept form $y=mx+b$:** Substitute $m=2$ and use point $(0,-2)$ to find $b$: $$-2 = 2 \times 0 + b \implies b = -2$$ 5. **Write the equation:** $$y = 2x - 2$$ 6. **Verify with another point:** For $(2,2)$: $$y = 2(2) - 2 = 4 - 2 = 2$$ which matches the point. **Final answer:** $$\boxed{y = 2x - 2}$$