Subjects algebra

Line Equations C790C2

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Question: Write the slope-intercept form of the equation of the line through the given points: 15) through: $(1,-5)$ and $(1,-4)$. 16) through: $(0,5)$ and $(1,1)$
1. **Problem 15:** Find the slope-intercept form of the line through points $(1,-5)$ and $(1,-4)$. 2. The slope formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ where $(x_1,y_1) = (1,-5)$ and $(x_2,y_2) = (1,-4)$. 3. Calculate the slope: $$m = \frac{-4 - (-5)}{1 - 1} = \frac{1}{0}$$ which is undefined. 4. Since the slope is undefined, the line is vertical and its equation is $$x = 1$$. --- 5. **Problem 16:** Find the slope-intercept form of the line through points $(0,5)$ and $(1,1)$. 6. Use the slope formula: $$m = \frac{1 - 5}{1 - 0} = \frac{-4}{1} = -4$$. 7. The slope-intercept form is $$y = mx + b$$. 8. Use point $(0,5)$ to find $b$: $$5 = -4 \times 0 + b \Rightarrow b = 5$$. 9. Therefore, the equation is: $$y = -4x + 5$$. **Final answers:** - Problem 15: $$x = 1$$ (vertical line) - Problem 16: $$y = -4x + 5$$