Subjects algebra

Line Gradient 5E783D

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Question: User: 17. Find the gradient of the line that passes through A $(-7, 2)$ and B $(2, 8)$, using $m = \frac{y_2 - y_1}{x_2 - x_1}$. m =
1. **State the problem:** Find the gradient $m$ of the line passing through points $A(-7, 2)$ and $B(2, 8)$. 2. **Formula:** The gradient formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ where $(x_1, y_1)$ and $(x_2, y_2)$ are coordinates of points $A$ and $B$ respectively. 3. **Substitute values:** Here, $x_1 = -7$, $y_1 = 2$, $x_2 = 2$, and $y_2 = 8$. So, $$m = \frac{8 - 2}{2 - (-7)}$$ 4. **Simplify numerator and denominator:** $$m = \frac{6}{2 + 7}$$ 5. **Add denominator terms:** $$m = \frac{6}{9}$$ 6. **Simplify the fraction:** $$m = \frac{\cancel{6}}{\cancel{9}} = \frac{2}{3}$$ 7. **Final answer:** The gradient of the line is $\boxed{\frac{2}{3}}$.