Line Slope 3D28B4

1. **State the problem:** We need to find the slope of a line that crosses the x-axis at approximately $(-2, 0)$ and the y-axis at approximately $(0, -2)$. 2. **Recall the formula for slope:** The slope $m$ of a line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Identify the points:** From the graph, the points are $(-2, 0)$ and $(0, -2)$. 4. **Calculate the slope:** $$m = \frac{-2 - 0}{0 - (-2)} = \frac{-2}{2}$$ 5. **Simplify the fraction:** $$m = \frac{\cancel{-2}}{\cancel{2}} = -1$$ 6. **Interpretation:** The slope of the line is $-1$, which means the line goes down one unit vertically for every one unit it moves horizontally to the right.