Subjects algebra

Line Slope C6F51A

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Question: What is the slope of the line that goes through points $A$ and $B$? What is another way to write the slope of the line? Point $A : (-1, 6)$ Point $B : (5, 4)$ Slope = vertical distance ------------------- horizontal distance = $6 - 4$ ------ $-1 - 5$ = $2$ --- $-6$ = [ ] $\frac{1}{3}$ $3$ $-\frac{1}{2}$ $-\frac{1}{3}$ $\frac{1}{2}$
1. **State the problem:** Find the slope of the line passing through points $A(-1,6)$ and $B(5,4)$. 2. **Recall the slope formula:** $$m = \frac{\text{vertical change}}{\text{horizontal change}} = \frac{y_2 - y_1}{x_2 - x_1}$$ where $(x_1,y_1)$ and $(x_2,y_2)$ are coordinates of points $A$ and $B$ respectively. 3. **Substitute the given points:** $$m = \frac{4 - 6}{5 - (-1)} = \frac{4 - 6}{5 + 1}$$ 4. **Calculate numerator and denominator:** $$m = \frac{-2}{6}$$ 5. **Simplify the fraction:** $$m = \frac{\cancel{-2}}{\cancel{6}} = -\frac{1}{3}$$ 6. **Interpretation:** The slope is $-\frac{1}{3}$, which means for every 3 units moved horizontally to the right, the line goes down by 1 unit. 7. **Another way to write the slope:** The slope can also be expressed as the ratio of vertical distance to horizontal distance: $$\text{slope} = \frac{\text{vertical distance}}{\text{horizontal distance}} = -\frac{1}{3}$$ **Final answer:** $$\boxed{-\frac{1}{3}}$$